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0=8x^2-5x-7
We move all terms to the left:
0-(8x^2-5x-7)=0
We add all the numbers together, and all the variables
-(8x^2-5x-7)=0
We get rid of parentheses
-8x^2+5x+7=0
a = -8; b = 5; c = +7;
Δ = b2-4ac
Δ = 52-4·(-8)·7
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{249}}{2*-8}=\frac{-5-\sqrt{249}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{249}}{2*-8}=\frac{-5+\sqrt{249}}{-16} $
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